Program to Cyclically rotate an array by one

Subarray with given sum

Given an array, rotate the array by one position in clock-wise direction.

Below question to rotate an array is taken from GeeksforGeeks platform .

To rotate an array following are steps :

1) Store last element in a variable say x.
2) Shift all elements one position ahead.
3) Replace first element of array with x.

Example 1:

N = 5
A[] = {1, 2, 3, 4, 5}
5 1 2 3 4

Example 2:

N = 8
A[] = {9, 8, 7, 6, 4, 2, 1, 3}
3 9 8 7 6 4 2 1

Your Task:  
You don't need to read input or print anything. Your task is to complete the function rotate() which takes the array A[] and its size N as inputs and modify the array in place.

Expected Time Complexity: O(N)
Expected Auxiliary Space: O(1)


Solution in Java

//{ Driver Code Starts
//Initial Template for Java

import java.util.*;
import java.lang.*;

class Technoname {
	public static void main(String[] args) throws IOException
	        BufferedReader br =
            new BufferedReader(new InputStreamReader(;
        int t =
            Integer.parseInt(br.readLine().trim()); // Inputting the testcases
            int n = Integer.parseInt(br.readLine().trim());
            int a[] = new int[n];
            // long getAnswer[] = new long[(int)(n)];
            String inputLine[] = br.readLine().trim().split(" ");
            for (int i = 0; i < n; i++) {
                a[i] = Integer.parseInt(inputLine[i]);
            Compute obj = new Compute();
            obj.rotate(a, n);
            StringBuilder output = new StringBuilder();
            for(int i=0;i<n;i++)
                output.append(a[i]+" ");

// } Driver Code Ends

//User function Template for Java

class Compute {
    public void rotate(int a[], int n)
        int x=a[n-1];
        for(int i=n-1;i>0;i--)       



Time Complexity: O(n), as we need to iterate through all the elements. Where n is the number of elements in the array.
Auxiliary Space: O(1), as we are using constant space.

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